Question

Alguém me ajuda nessa questão.Por favor

Desde já agradeço

Answer 1

$A\timesB=\left[\begin{array}{cc}2&6\\-1&0\end{array}\right] \times \left[\begin{array}{c}4\\3\end{array}\right] =\left[\begin{array}{c}2\times4+6\times3\\-1\times4+0\times 3\end{array}\right]=\left[\begin{array}{c}26\\-4\end{array}\right]\\ \\ \\ A\times C \rightarrow \ impossivel\\ \\ B \times C=\left[\begin{array}{c}4\\3\end{array}\right]\times [ 1 \ \ -2]=\left[\begin{array}{c}4 \times 1\\3\times (-2)\end{array}\right]=[4 \ \ -6]$

$A^2=\left[\begin{array}{cc}2&6\\-1&0\end{array}\right] \times \left[\begin{array}{cc}2&6\\-1&0\end{array}\right] =\left[\begin{array}{cc}2\times2+6\times(-1)&2\times6+6\times 0\\-1\times2+0\times(-1)&-1\times6+0\times0\end{array}\right] =\left[\begin{array}{cc}-2&12\\-2&-6\end{array}\right]$

$B^2=impossivel$