Matemática, perguntado por ogoin16, 1 ano atrás

Alguém me ajuda nessa questão de números complexos, por favor?

Anexos:

Soluções para a tarefa

Respondido por LuanaSC8
1
Sendo:~~~~p_1=6+8i~~~~e~~~~p_2=6-2i~,~~~~quanto~~~~vale~~~~ \dfrac{p_1}{p_2} ~?\\\\\\\\ \dfrac{6+8i}{6-2i}\to\\\\\\\dfrac{6+8i}{6-2i}\times \dfrac{6+2i}{6+2i}\to\\\\\\ \dfrac{36+12i+48i+16i^2}{36+12i-12i-4i^2}\to\\\\\\ \dfrac{36+60i+16i^2}{36-4i^2}\to




Lembrando~~que~~i^2=-1\\\\\\ \dfrac{36+60i+16i(-1)}{36-4(-1)}\to\\\\\\ \dfrac{36+60i-16}{36+4}\to \\\\\\ \dfrac{20+60i}{40}\to ~~Simplifique ~~por~~20:  \\\\ \\ \large\boxed{\boxed{\dfrac{1+3i}{2}}}\\\\\\\\\\\\ Resposta\to~~~~Letra~~~A)~\dfrac{1+3i}{2}
Perguntas interessantes