Question

alguém me ajuda nessa questão de função do 1° grau, por favor eu necessito​

Answer 1

a)

$f(3) = \frac{3}{2} - 3.3 = \frac{3}{2} - 9 \\ f(3) = \frac{3 - 18}{2} = - \frac{15}{2}$

b)

$f( - 7) = \frac{3}{2} - 3.( - 7) \\ f( - 7) = \frac{3}{2} + 21 = \frac{3 + 42}{2} \\ f( - 7) = \frac{45}{2}$

c)

$f( - \frac{10}{5} ) = f( - 2) \\ f( - 2) = \frac{3}{2} - 3.( - 2) \\ f( - 2) = \frac{3}{2} + 6 = \frac{3 + 12}{2}$

$f( - 2) = \frac{15}{2}$

d)

$f( - \frac{1}{2} ) = \frac{3}{2} - 3.( - \frac{1}{2} ) \\ f( - \frac{1}{2}) = \frac{3}{2} + \frac{3}{2} = 3$

Answer 2

Resposta:

Explicação passo-a-passo:

Olá!

Basta substituir no x da função, o valor entre parênteses. Dessa forma:

$f(x) = \frac{3}{2} -3x$

$f(3) = \frac{3}{2} -3.3$

$f(3) = \frac{3}{2} -9$

$f(3) = \frac{3}{2} -\frac{18}{2}$

$f(3) = \frac{-15}{2}$

$f(-7) = \frac{3}{2} -3(-7)$

$f(-7) = \frac{3}{2} + 21$

$f(-7) = \frac{3}{2} +\frac{42}{2}$

$f(-7) =\frac{45}{2}$

$f(\frac{-10}{5}) = \frac{3}{2} -3(\frac{-10}{5})$

$f(\frac{-10}{5}) = \frac{3}{2} +\frac{30}{5}$

$f(\frac{-10}{5}) = \frac{15}{10} +\frac{60}{10}$

$f(\frac{-10}{5}) = \frac{75}{10}$

$f(\frac{-10}{5}) = 7,5$

$f(\frac{-1}{2}) = \frac{3}{2} -3(\frac{-1}{2})$

$f(\frac{-1}{2}) = \frac{3}{2} + \frac{3}{2}$

$f(\frac{-1}{2}) = \frac{6}{2}$

$f(\frac{-1}{2}) = 3$

Espero ter ajudado :/

Boa sorte!