Question

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Encontre x' e x'' X²-5x+6=0​

Answer 1

$\large\boxed{\begin{array}{l}\rm x^2-5x+6=0\\\begin{cases}\sf a=1\\\sf b=-5\\\sf c=6\end{cases}\\\rm\Delta=b^2-4ac\\\rm\Delta=(-5)^2-4\cdot1\cdot6\\\rm\Delta=25-24\\\rm\Delta=1\\\rm x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\\rm x=\dfrac{-(-5)\pm\sqrt{1}}{2\cdot1}\\\\\rm x=\dfrac{5\pm1}{2}\begin{cases}\rm x'=\dfrac{5+1}{2}=\dfrac{6}{2}=3\\\\\rm x''=\dfrac{5-1}{2}=\dfrac{4}{2}=2\end{cases}\end{array}}$