Question

Alguém me ajuda aí please!?


TRIGONOMETRIA(ARCOS)​

Answer 1

Resposta:

ITEM (A)

Explicação passo-a-passo:

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$\sf{6 \tan( \frac{\pi}{6} ) + 4 \sin( \frac{7\pi}{3} ) - \cos( \frac{7\pi}{6} ) } \\ \\ \sf{6 \times \frac{ \sqrt{3} }{3} + 4 \times \frac{ \sqrt{3} }{2} - \left( - \frac{ \sqrt{3} }{2} \right)} \\ \\ \sf{6 \times \frac{ \sqrt{3} }{3} + 4 \times \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{2 \sqrt{3} + 4 \times \frac{ \sqrt{3} }{2} + \frac{3}{2} } \\ \\ \sf{2 \sqrt{3} + 2 \sqrt{3} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{ \frac{2 \sqrt{3} }{1} + 2 \sqrt{3} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{ \frac{2 \sqrt{3} }{1} + \frac{2 \sqrt{3} }{1} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{ \frac{2 \times 2 \sqrt{3} }{2 \times 1} + \frac{2 \times 2 \sqrt{3} }{2 \times 1} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{ \frac{4 \sqrt{3} }{2} + \frac{4 \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} } \\ \\ \sf{ \frac{4 \sqrt{3} + 4 \sqrt{3} + \sqrt{3} }{2} } \\ \\ \sf{ \frac{9 \sqrt{3} }{2} } \\ \\ \sf{ \sqrt{ \frac{9 \sqrt{3} }{2} } } \\ \\ \sf{ \frac{ \sqrt{9 \sqrt{3} } }{ \sqrt{2} } } \\ \\ \sf{ \frac{ \sqrt{ {3}^{2} \times \sqrt{3} } }{ \sqrt{2} } } \\ \\ \sf{ \frac{ \sqrt{ {3}^{2} } \sqrt{ \sqrt{3} } }{ \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt{ \sqrt{3} } }{ \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[2 \times 2]{3} }{ \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[4]{3} }{ \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[4]{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[4]{3} \sqrt{2} }{ \sqrt{2} \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[4]{3} \sqrt[4]{ {2}^{2} } }{ \sqrt{2} \sqrt{2} } } \\ \\ \sf{ \frac{3 \sqrt[4]{3} \sqrt[4]{ {2}^{2} } }{2} } \\ \\ \sf{ \frac{3 \sqrt[4]{3 \times {2}^{2} } }{2} } \\ \\ \sf{ \frac{3 \sqrt[4]{3 \times 4} }{2} } \\ \\ \red{ \boxed{ \green{ \boxed{ \pink{ \boxed{ \sf{ \frac{ 3 \sqrt[4]{12} }{2} }} }} } } }$

$\mathcal{ATT : ARMANDO} \\ \mathfrak{\small04\diagup01\diagup2021} \\ \mathfrak{\small{12} :{12} \: \: pm}$