Question

alguem me ajuda a responder pfv
A) 36=4ײ
B) ײ-5×=0
C) -7×+4ײ=0
D) -4ײ+9×=0
E) 3ײ+5×=0
F) 4ײ-12×=0
G) x²=-x
H) 7x²+14×=0
I) -2ײ+10×=0​

Answer 1

Explicação passo-a-passo:

a) $36=4x^2$

$x^2=\dfrac{36}{4}$

$x^2=9$

$x=\pm\sqrt{9}$

$x'=3$

$x"=-3$

b) $x^2-5x=0$

$x\cdot(x-5)=0$

$x'=0$

$x-5=0~\longrightarrow~x"=5$

c) $-7x+4x^2=0$

$x\cdot(-7+4x)=0$

$x'=0$

$-7+4x=0~\longrightarrow~4x=7~\longrightarrow~x"=\dfrac{7}{4}$

d) $-4x^2+9x=0$

$x\cdot(-4x+9)=0$

$x'=0$

$-4x+9=0~\longrightarrow~4x=9~\longrightarrow~x=\dfrac{9}{4}$

e) $3x^2+5x=0$

$x\cdot(3x+5)=0$

$x'=0$

$3x+5=0~\longrightarrow~3x=-5~\longrightarrow~x=\dfrac{-5}{3}$

f) $3x^2-12x=0$

$3x\cdot(x-4)=0$

$3x=0~\longrightarrow~x'=0$

$x-4=0~\longrightarrow~x"=4$

g) $x^2=-x$

$x^2+x=0$

$x\cdot(x+1)=0$

$x'=0$

$x+1=0~\longrightarrow~x"=-1$

h) $7x^2+14x=0$

$7x\cdot(x+2)=0$

$7x=0~\longrightarrow~x'=0$

$x+2=0~\longrightarrow~x"=-2$

i) $-2x^2+10x=0$

$2x\cdot(-x+5)=0$

$2x=0~\longrightarrow~x'=0$

$-x+5=0~\longrightarrow~x"=5$

Answer 2

Resposta:

A) 36 = 4x²

x² = 9

x = ±√9

x = ± 3

B) x² - 5x = 0

x(x - 5) = 0

x' - 5 = 0

x' = 5

x" = 0

C) -7x + 4x² = 0

x(-7 + 4x) = 0

4x' = 7

x' = 7/4

x" = 0

D) -4x² + 9x = 0

x(-4x + 9) = 0

4x' = 9

x' = 9/4

x" = 0

E) 3x² + 5x = 0

x(3x + 5) = 0

3x' = -5

x' = -5/3

x" = 0

F) 4x² - 12x = 0

4x(x - 3) = 0

x' = 3

x" = 0

x(4x - 12x) = 0

12x' = 4x'

3x' = x'

x = 0

G) x² = -x

x = 0

H) 7x² + 14x = 0

7x(x + 2) = 0

x' = -2

x" = 0

I) -2x² + 10x = 0

2x(-x + 5) = 0

x' = 5

x" = 0

Espero Ter Ajudado !!