Question

Alguem me ajuda a resolver -x2+x+12=y

Answer 1

$-x^2+x+12=y\\ \mathrm{Dominio\:de\:}\:-x^2+x+12\::\quad \begin{bmatrix}\mathrm{Solucao:}\:&\:-\infty \:<x<\infty \\ \:\mathrm{Notacao\:intervalo}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}\\ \mathrm{Imagem\:de\:}-x^2+x+12:\quad \begin{bmatrix}\mathrm{Solucao:}\:&\:f\left(x\right)\le \frac{49}{4}\:\\ \:\mathrm{Notacao\:intervalo}&\:(-\infty \:,\:\frac{49}{4}]\end{bmatrix}$

$\mathrm{Pontos\:de\:interseccao\:com\:o\:eixo\:de}\:-x^2+x+12:\quad \mathrm{X\:intersepta}:\:\left(-3,\:0\right),\:\left(4,\:0\right),\:\mathrm{Y\:intersepta}:\:\left(0,\:12\right)$

$\mathrm{Vertice\:de}\:-x^2+x+12:\quad \mathrm{Maximo}\space\left(\frac{1}{2},\:\frac{49}{4}\right)$