Question

Alguém me ajuda a resolver isso

Answer 1

7-

a$10^{-2} = \frac{1}{10}^{2} = \frac{1}{10} .\frac{1}{10} = \frac{1}{100}$)

b) $(\frac{-5}{8})^{-2} = (\frac{-8}{5})^2 = (\frac{-8}{5}) . (\frac{-8}{5}) = \frac{64}{25}$

c) $(\frac{-3}{2})^{-3} = (\frac{-2}{3})^{3} = (\frac{-2}{3}) . (\frac{-2}{3}) . (\frac{-2}{3}) = (\frac{-8}{27})$

d) $(-3)^{-3} = (\frac{-1}{3})^{3} = (\frac{-1}{3}) . (\frac{-1}{3}) .(\frac{-1}{3}) =(\frac{-1}{27})$

e) $(\frac{2}{3})^{-2} = \frac{3}{2}^2 = \frac{3}{2} . \frac{3}{2} = \frac{9}{4}$

f) $(\frac{1}{2})^{-5} = (\frac{2}{1})^5 = \frac{2}{1} . \frac{2}{1} . \frac{2}{1} . \frac{2}{1} .\frac{2}{1} =\frac{32}{1} = 32$

8- Desafio:

$- (-1)^{3} - (-1)^{4} + (-2)^{2} -2^{3} + (-1 -1)^{2} = \\1^3 + 1^4 + (-2)^2 - 2^3 + (-2)^2=\\1 + 1 + 4 - 8 + 4 =\\2$