Question

alguém me ajuda a resolver essa conta

-2x²+10x=0​

Answer 1

Resposta:

$-2x^{2} +10x=0$

coeficientes: a=-2, b=10, c=0

$x=\frac{-b+-\sqrt{b^{2}-4.a.c } }{2.a} \\ \\ x=\frac{-10+-\sqrt{(-10)^{2} }-4.(-2).0 }{2.(-2)} \\ \\ x=\frac{-10+-\sqrt{100-0} }{-4} \\ \\ x=\frac{-10+-\sqrt{100} }{-4} \\ \\ x=\frac{-10+-10}{-4} \\ \\ x'=\frac{-10+10}{-4} =\frac{0}{-4} =0\\ \\ x''=\frac{-10-10}{-4} =\frac{-20}{-4} =+5\\ \\ \\ S~~\left \{ {{0,~~5} {}} \}$