Question

Alguém me ajuda a resolver ?

Answer 1

Bom Dia!

$\frac{3}{x+2}- \frac{1}{x-1} = \frac{2}{x}$ * $x*(x+2)(x-1)$
$3(x-1)*x - 1x(x+2)=2(x+2)(x-1)$
$3x^2-3x-x^2-2x=(2x+4)(x-1)$
$3x^2-3x-x^2-2x=2x^2-2x+4x-4$
$3x^2-3x-x^2-2x=2x^2+2x-4$
$2x^2-5x=2x^2+2x-4$
$-7x=-4$

$\boxed { \boxed { x= \frac{4}{7} } }$

Bons estudos!!