Question

alguem me ajuda ? (4^x)^x-1 = 16

Answer 1

4 ^x(x-1) = 4^2
x² - x = 2
x² - x - 2 = 0

(x-2)(x+1)
x-2=0
x= 2

x+1=0
x = -1

{2,-1}