Question

Alguém explica isso passo a passo? 6x²-10x+3=0

Por favor!;(

Answer 1

Resposta:

$x'=\frac{5-\sqrt{7} }{6}\\\\x''=\frac{5+\sqrt{7} }{6}$

Explicação passo a passo:

$6x^{2} -10x+3=0\\\\Para\ ax^{2} +bx+c=0:\\a=6\ ,\ b=(-10)\ ,\ c=3\\\\Formula\ de\ Bhaskara:\ x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a}\\\\x=\frac{-(-10)\pm\sqrt{(-10)^{2} -4\times6\times3} }{2\times6}\\\\x=\frac{10\pm\sqrt{100 -24\times3} }{12}\\\\x=\frac{10\pm\sqrt{100 -72} }{12}\\\\x=\frac{10\pm\sqrt{28} }{12}\\\\x=\frac{10\pm\sqrt{4\times7} }{12}\\\\x=\frac{10\pm\sqrt{4}\sqrt{7} }{12}\\\\x=\frac{10\pm2\sqrt{7} }{12}\\\\x=\frac{5\pm\sqrt{7} }{6}$

$x'=\frac{5-\sqrt{7} }{6}\\\\x''=\frac{5+\sqrt{7} }{6}$