Matemática, perguntado por ramoneric422, 6 meses atrás

Alguém consegue montar a conta

Anexos:

Soluções para a tarefa

Respondido por tatianapatricio1987
1

Resposta:

x + y =  - 2

x.y = -  8

x =   - \frac{8}{y}

 \frac{8}{y}  + y = 2

 -   \frac{8 +  {y}^{2} }{y}  = -  2

 - 8 +  {y}^{2}  =  - 2y

 {y}^{2}   +  2y  -  8 = 0

s =   \frac{ - b}{a}

s =  -  \frac{2}{1}

s =  - 2

p =  \frac{c}{a}

p =  -  \frac{8}{1}

p =  - 8

x1 =   2 \:  \: x2 = -  4

 x =   2 \:  \: y = -  4

Respondido por laraferminosantos
0

\left \{ {{x+y=-2} \atop {xy=-8}} \right. \\\\x+y=-2\\\\x= -2-y\\\\xy=-8\\\\(-2-y)y=-8\\\\-2y-y^{2} = -8  (-1)\\\\2y+y^{2} =8\\\\y^{2}+2y+8=0 \\\\a=1 \\ b=2\\ c=8\\\\y=\frac{-b+-\sqrt{\delta}}{2a} \\\\

Δ=b^{2}-4ac

Δ= 2²-4.1.8

Δ=-28(-1)

Δ= 28

y= \frac{-2-+\sqrt{28} }{2*1} \\\\y^{'} = \frac{-2+\sqrt{28} }{2} \\\\\\y^{'} = \frac{-2+2\sqrt{7}  }{2} \\\\\\y^{'} = -2\sqrt{28} \\\\y^{''} = \frac{-2-\sqrt{28} }{2} \\\\\\y^{'} = +2\sqrt{28}

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