Question

alguém consegue me explicar passo a passo como faz o 9? obggg

Answer 1

Eu consigo:

$(\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}})^2=\\ \\ (\sqrt{2+\sqrt{3}})^2+2(\sqrt{2+\sqrt{3}})(\sqrt{2-\sqrt{3}})+(\sqrt{2-\sqrt{3}})^2=\\ \\ 2+\sqrt{3}+2(\sqrt{(2+\sqrt3)(2-\sqrt3})+2-\sqrt{3}=\\ \\ 2+2(\sqrt{4-2\sqrt3+2\sqrt3-3})+2=\\ \\ 2+2(\sqrt{4-3})+2=\\ \\ 2+2.\sqrt1+2=2+2+2=6$