Question

alguém consegue fazer a “a” e a “b” pra mim

Answer 1

$f(x) = x^2 - 3x \\\\ a) f \left(-\frac{1}{4} \right) = \left(- \frac{1}{4} \right)^2 - 3 \left( - \frac{1}{4} \right) \\\\ f \left(-\frac{1}{4} \right ) = \frac{1}{16} + \frac{3}{4} \\\\ \boxed{ f \left(-\frac{1}{4} \right) = \frac{13}{16} }$

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$b) \: f \left(-3 \right) = (-3)^2 - 3(-3) \\\\ f \left(-3 \right) = 9 + 9 \\\\ \boxed{f \left(-3 \right) = 18}$