Question

Alguém ajudaaaaaa pfvrrr​

Answer 1

$\left(\left(\frac{2}{3}\right)^0\right)^4+\left(0.25^3\right)^0+\left(3^2\right)^3=731$

$\left(\left(\frac{2}{3}\right)^0\right)^4+\left(0.25^3\right)^0+\left(3^2\right)^3$

$\mathrm{Aplicar\:a\:regra}\:a^0=1,\:a\ne \:0$

$\left(\frac{2}{3}\right)^0=1,\:\left(0.25^3\right)^0=1$

$=1^4+1+\left(3^2\right)^3$

$1^{4} =1\\(3^{3})^{3} = 3^{6}$

$=1+1+3^6$

$=729+2$

$=731$