Question

Alguem ajuda ai na questao 7

Answer 1

y = (2x-1) / (3x)

y = (2x/3x) - (1/3x)

y = (2/3) - (1/3x)

f^-1:

x = (2/3) - (1/3y)

x - (2/3) = -(1/3y)

(x - (2/3)).(3y) = -1

3y = (-1) / (x-(2/3))

y = (-1) / (x-(2/3).(3)

y = (-1) / (3x - 2)

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f^-1 ( 1) :

y = (-1) / (3.1 - 2)

y = (-1) / (3-2)

y = (-1) / 1

y = -1