Alguém
[3^8/(3^2)^3]/[(3^-3)^-2x3^4]^-2
Anexos:
Soluções para a tarefa
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Olá.
Temos a expressão:
![\Large\begin{array}{l}\mathsf{[3^8/(3^2)^3]^{-1}/[(3^{-3})^{-2}\cdot3^4]^{-2}}\end{array}](https://tex.z-dn.net/?f=%5CLarge%5Cbegin%7Barray%7D%7Bl%7D%5Cmathsf%7B%5B3%5E8%2F%283%5E2%29%5E3%5D%5E%7B-1%7D%2F%5B%283%5E%7B-3%7D%29%5E%7B-2%7D%5Ccdot3%5E4%5D%5E%7B-2%7D%7D%5Cend%7Barray%7D "\Large\begin{array}{l}\mathsf{[3^8/(3^2)^3]^{-1}/[(3^{-3})^{-2}\cdot3^4]^{-2}}\end{array}")
Usaremos as seguintes propriedades de potência:
Vamos aos cálculos:
![\Large\begin{array}{l}
\mathsf{[3^8/(3^2)^3]^{-1}/[(3^{-3})^{-2}\cdot3^4]^{-2}}\\\\
\mathsf{[3^8/3^{2\cdot3}]^{-1}/[3^{-3\cdot(-2)}\cdot3^4]^{-2}}\\\\
\mathsf{[3^8/3^{6}]^{-1}/[3^{6}\cdot3^4]^{-2}}\\\\
\mathsf{[3^{8-6}]^{-1}/[3^{6+4}]^{-2}}\\\\
\mathsf{[3^{2}]^{-1}/[3^{10}]^{-2}}\\\\
\mathsf{\left[\dfrac{1}{3^{2}}\right]^{1}/\left[\dfrac{1}{3^{10}}\right]^{2}}\\\\
\mathsf{\dfrac{1}{3^{2\cdot1}}/\dfrac{1}{3^{10\cdot2}}}\\\\
\mathsf{\dfrac{1}{3^{2}}/\dfrac{1}{3^{20}}}\\\\
\end{array}](https://tex.z-dn.net/?f=%5CLarge%5Cbegin%7Barray%7D%7Bl%7D%0A%5Cmathsf%7B%5B3%5E8%2F%283%5E2%29%5E3%5D%5E%7B-1%7D%2F%5B%283%5E%7B-3%7D%29%5E%7B-2%7D%5Ccdot3%5E4%5D%5E%7B-2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5B3%5E8%2F3%5E%7B2%5Ccdot3%7D%5D%5E%7B-1%7D%2F%5B3%5E%7B-3%5Ccdot%28-2%29%7D%5Ccdot3%5E4%5D%5E%7B-2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5B3%5E8%2F3%5E%7B6%7D%5D%5E%7B-1%7D%2F%5B3%5E%7B6%7D%5Ccdot3%5E4%5D%5E%7B-2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5B3%5E%7B8-6%7D%5D%5E%7B-1%7D%2F%5B3%5E%7B6%2B4%7D%5D%5E%7B-2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5B3%5E%7B2%7D%5D%5E%7B-1%7D%2F%5B3%5E%7B10%7D%5D%5E%7B-2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7B1%7D%7B3%5E%7B2%7D%7D%5Cright%5D%5E%7B1%7D%2F%5Cleft%5B%5Cdfrac%7B1%7D%7B3%5E%7B10%7D%7D%5Cright%5D%5E%7B2%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B1%7D%7B3%5E%7B2%5Ccdot1%7D%7D%2F%5Cdfrac%7B1%7D%7B3%5E%7B10%5Ccdot2%7D%7D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B1%7D%7B3%5E%7B2%7D%7D%2F%5Cdfrac%7B1%7D%7B3%5E%7B20%7D%7D%7D%5C%5C%5C%5C%0A%5Cend%7Barray%7D "\Large\begin{array}{l}
\mathsf{[3^8/(3^2)^3]^{-1}/[(3^{-3})^{-2}\cdot3^4]^{-2}}\\\\
\mathsf{[3^8/3^{2\cdot3}]^{-1}/[3^{-3\cdot(-2)}\cdot3^4]^{-2}}\\\\
\mathsf{[3^8/3^{6}]^{-1}/[3^{6}\cdot3^4]^{-2}}\\\\
\mathsf{[3^{8-6}]^{-1}/[3^{6+4}]^{-2}}\\\\
\mathsf{[3^{2}]^{-1}/[3^{10}]^{-2}}\\\\
\mathsf{\left[\dfrac{1}{3^{2}}\right]^{1}/\left[\dfrac{1}{3^{10}}\right]^{2}}\\\\
\mathsf{\dfrac{1}{3^{2\cdot1}}/\dfrac{1}{3^{10\cdot2}}}\\\\
\mathsf{\dfrac{1}{3^{2}}/\dfrac{1}{3^{20}}}\\\\
\end{array}")
Na divisão de entre duas frações, invertemos a segunda fração, trocando o sinal de divisão por um de multiplicação:
Qualquer dúvida, deixe nos comentários.
Bons estudos.
Temos a expressão:
Usaremos as seguintes propriedades de potência:
Vamos aos cálculos:
Na divisão de entre duas frações, invertemos a segunda fração, trocando o sinal de divisão por um de multiplicação:
Qualquer dúvida, deixe nos comentários.
Bons estudos.
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