Question

algm me ajuda a resolver a 32

Answer 1

   [ ( 2a / x-3 ) + ( a/x ) - ( 2ax / x²-3x ) ] × ( x / 2a ) =

= [ ( 2a / x ) - ( 2a / 3 ) + ( a / x ) - ( 2ax / x² ) + ( 2ax / 3x ) ] × ( x / 2a ) =

= ( 2ax / 2ax ) - ( 2ax / 6a ) + ( ax / 2ax ) - ( 2ax² / 2ax² ) + ( 2ax² / 6ax ) =

= 1 - ( x / 3 ) + ( 1 / 2 ) - 1 + ( x / 3 ) =

= 1 + ( 1 / 2 ) - 1 =

=  1 / 2