Question

algem mi diz com faz essas duas equaçoes?
n2+10n+9=0
x2+20x+19=0

Answer 1

Resolva pela fórmula de báskara
n^2+10n+9=0
delta=b^2-4ac
delta=10^2-4.1.9
delta=100-36
delta=64
n=-b-/+ raiz de delta/2a
n=-10-8/2.1
n=-18/2
n=-9
n=-10+8/2.1
n=-2/2
n=-1
x^2+20x+19=0
delta=b^2-4ac
delta=20^2-4.1.19
delta=400-76
delta=324
x=-b-/+ raiz de delta/2a
x=-20-18/2.1
x=-38/2
x=-19
x=-20+18/2.1
x=-2/2
x=-1

Answer 2

n² + 10n + 9 = 0
a = 1; b = 10; c = 9
Delta:
Δ = b² - 4ac
Δ = 10² - 4 * 1 * 9
Δ = 100 - 36
Δ = 64
Bhaskara:
n = - b ± √Δ / 2a
n = - 10 ± √64 / 2 * 1
n = - 10 ± 8 / 2
n' = - 10 + 8 / 2 = -2 / 2 = -1
n'' = - 10 - 8 / 2 = -18 / 2 = -9
S = {-9, -1}

x² + 20 + 19 = 0
Delta:
Δ = 20² - 4 * 1 * 19
Δ = 400 - 76
Δ = 324
Bhaskara:
x = - 20 ± √324 / 2 * 1
x = - 20 ± 18 / 2
x' = - 20 + 18 / 2 = -2 / 2 = -1
x'' = - 20 - 18 / 2 = -38 / 2 = -19
S = {-19, -1}

Espero ter ajudado. Valeu!