Álgebra Linear
Verificar se u e v são linearmente dependente ou linearmente independente nos casos:
a) u=(1,2) e v=(3,6)
b) u=(4,-6) e v=(-2,3)
c) u=(6,8) e v=(-2,-3)
d) u=(0,0) e v=(1,5)
Soluções para a tarefa
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Iguala as coordenadas dos vetores
A)

Vetores L.D
B)

Vetores L.D
C)

Vetores L.I
D)

Iguala as coordenadas dos vetores
A)
Vetores L.D
B)
Vetores L.D
C)
Vetores L.I
D)
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