Question

ajuuudaaaa pfv!!!!!!!!!!!!!!!

Answer 1

Explicação passo-a-passo:

$1)\\A) \left \{ {{4x=2+y \atop {4x-y=10} \right. \\y=4x-2\\4x-(4x-2)=10\\+2=10 \\Impossivel \\\\B)\left \{ {{x+2y=5} \atop {2x+3y=7}} \right. \\x=5-2y\\2*(5-2y)+3y=7\\10-4y+3y=7\\-y=-3\\y=3\\x=-1\\\\2)\left \{ {{3S+1G=12} \atop {2S+3G=15}} \right.\\G=12-3S\\2S+3*(12-3S)=15\\2S+36-9S=15\\-7S=-21\\S=3\\G=3$