Question

ajudinha!
$2t {}^{2} + t - 36 = 0$
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Answer 1

Resposta:

$2t ^ { 2 } +t-36=0 \\ t=\frac{-1±\sqrt{1^{2}-4\times 2\left(-36\right)}}{2\times 2} \\ t=\frac{-1±\sqrt{1-4\times 2\left(-36\right)}}{2\times 2} \\ t=\frac{-1±\sqrt{289}}{2\times 2} \\ t=\frac{-1±17}{2\times 2} \\ t=\frac{-1±17}{4} \\ t1=\frac{16}{4} \\ t1=4 \\ t2=\frac{-18}{4} \\ t2=-\frac{9}{2}$