Question

ajudemmmmmmm equação de 2°grau ​

Answer 1

a)

$x^2-8x=0\ \therefore\ x(x-8)=0\ \therefore\\\\ \boxed{x=0}\ \ \text{ou}\ \ x-8=0\ \therefore\ \boxed{x=8}$

b)

$5x^2-10=0\ \therefore\ x^2=2\ \therefore\ \boxed{x=\pm\sqrt{2}}$

c)

$ax^2+bx+c=0\ \to\ x^2-3x+2=0\\\\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(1)(2)}}{2(1)}=$

$=\dfrac{3\pm\sqrt{1}}{2}=\dfrac{3\pm1}{2}\ \therefore\ \boxed{x=1}\ \ \text{ou}\ \ \boxed{x=2}$