Question

ajudem sem zoeira pvr x^2-2x/3x-6=1​

Answer 1

(x^2-2x) / (3x-6)=1/1

multiplique em cruz

x^2 - 2x = 3x -6

x^2-2x -3 x + 6 =0

x^2 - 5x + 6 =0

baskara

(5+ - v25-24)/2=(5+ - 1)/2

x'=3

x"=2

ESPERO TER AJUDADO !

att:${\blue{♡leticia♡}}$

Answer 2

$x^{2} -\dfrac{2x}{3x-6} =1\\ \\ \\ x^{2} -2x=1\cdot(3x-6)\\ \\ x^{2} -2x=3x-6\\ \\ x^{2} -2x-3x+6=0\\ \\\\ x^{2} -5x+6=0~~~~\to ~~~~~Bhaskara\\ a=1~~,~~b=-5~~,~~c=6\\ \\ \\ \dfrac{-b\pm\sqrt{b^{2} -4\cdot a\cdot c} }{2\cdot a} ~~=~~\dfrac{-(-5)\pm\sqrt{5^{2}-4\cdot 1\cdot 6 } }{2\cdot 1} ~~=~~\dfrac{5\pm\sqrt{25-24} }{2} ~~=~~\dfrac{5\pm\sqrt{1} }{2} \\ \\ \\ \\ x'=\dfrac{5\pm1}{2} ~~=~~\dfrac{6}{2} ~~=~~\boxed{x'=3} \\ \\ \\ x''=\dfrac{5\pm1}{2} ~~=~~\dfrac{4}{2} ~~=~~\boxed{x''=2}$

Resposta:

x' = 3

x'' = 2

:)