Question

Ajudem,se puder explicar tb, aceito

Answer 1

$\frac{x-\frac{1}{3}}{\frac{1}{4}}-\frac{1}{12}=\frac{x+\frac{1}{3}}{\frac{4}{3}} \\ \\ \frac{\frac{3x-1}{3}}{\frac{1}{4}}-\frac{1}{12}=\frac{\frac{3x+1}{3}}{\frac{4}{3}} \\ \\ \frac{3x-1}{3}.4-\frac{1}{12}=\frac{3x+1}{3}.\frac{3}{4} \\ \\ \frac{12x-4}{3}-\frac{1}{12}=\frac{3x+1}{4} \\ \\ 4(12x-4)-1=3(3x+1) \\ \\ 48x-16-1=9x+3 \\ \\ 48x-9x=3+16+1 \\ \\ 39x=20 \\ \boxed{x=\frac{20}{39}}$