Question

AJUDEM POR FAVOR EU IMPLORO


$log_{ \sqrt{4} }(16)$

$log_{3}\sqrt[3]{27}$

$log_{36} \frac{1}{6}$

$log_{ \frac{1}{3} }9$
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Answer 1

$log_{ \sqrt{4} }(16) \\ { \sqrt{4} }^{ \: ?} = 16 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \downarrow \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4 \times 4 \\ { \sqrt{4} }^{ \: 4} = 16 \\ \sqrt[ \cancel{2}]{ {4}^{ \cancel{2}} \times {4}^{ \cancel{2}} } = 16 \\ 4 \times 4 = 16 \: ✔ \\ Resposta: \: \boxed{4}$

$log_{3}\sqrt[3]{27} \\ log_{3}( \sqrt[ \cancel{3}]{ {3}^{ \cancel{3}} } ) \\ log_{3}(3) \\ \boxed{1}$

$log_{36} \left(\frac{1}{6} \right) \\ log_{ {6}^{2} }( {6}^{ - 1} ) \\ \frac{ - 1}{2} \times log_{6}(6) \\ - \frac{1}{2} \times 1 \\ \boxed{ - \frac{1}{2} }$

$log_{ \frac{1}{3} }(9) \\ log_{ {3}^{ - 1} }( {3}^{2} ) \\ \frac{2}{ - 1} \times log_{3}(3) \\ - 2 \times 1 \\ \boxed{ - 2}$

$Espero \: ter \: Ajudado \\ MATEMÁTICA\\ \displaystyle\int_ \empty ^ \mathbb{C}     \frac{ - b \: ± \:  \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} d{ t } \boxed{ \boxed{ \mathbb{\displaystyle\Re}\sf{ \gamma  \alpha }\tt{ \pi}\bf{ \nabla}}}$