AJUDEM POR FAVOR DELTA
x (ao quadrado) - 81 = 0
A resposta da + é - 9
Usuário anônimo:
x² - 81 = 0 > x² = 81 > x = raiz quadrada de 9 > x = +- 9
Soluções para a tarefa
Respondido por
1
x² -81=0
x² = 81
x=![\sqrt{81} \sqrt{81}](https://tex.z-dn.net/?f=+%5Csqrt%7B81%7D+)
x = + 9
Bons estudos..(;
x² = 81
x=
x = + 9
Bons estudos..(;
Respondido por
1
Eu fiz ela sem Bhaskara desse jeito agorinha:
![x^{2} -81=0\to \\\\ x^{2} =81\to \\\\ x=\pm \sqrt{81} \to \\\\ x\pm 9\\\\\\ S=(-9;9) x^{2} -81=0\to \\\\ x^{2} =81\to \\\\ x=\pm \sqrt{81} \to \\\\ x\pm 9\\\\\\ S=(-9;9)](https://tex.z-dn.net/?f=+x%5E%7B2%7D+-81%3D0%5Cto+%5C%5C%5C%5C+x%5E%7B2%7D+%3D81%5Cto+%5C%5C%5C%5C+x%3D%5Cpm+%5Csqrt%7B81%7D+%5Cto+%5C%5C%5C%5C+x%5Cpm+9%5C%5C%5C%5C%5C%5C+S%3D%28-9%3B9%29)
Mas vou colocar a fórmula de Bhaskara aqui tbm:
![x^{2} -81=0\\\\ a=1;b=0;c=-81\\\\\\ \Delta=b^2-4ac\to \Delta=0^2-4*1*(-81)\to \Delta=0+324\to \Delta=324\\\\ x'=x'' \\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-0\pm \sqrt{324} }{2*1} \to x= \frac{-0\pm 18 }{2} \to \\\\\\ x= \frac{-0+18 }{2} \to x= \frac{18 }{2} \to x'=9\\\\\\ x''= \frac{-0- 18 }{2} \to x= \frac{-18 }{2} \to x''=-9\\\\\\\\ S=(-9;9) x^{2} -81=0\\\\ a=1;b=0;c=-81\\\\\\ \Delta=b^2-4ac\to \Delta=0^2-4*1*(-81)\to \Delta=0+324\to \Delta=324\\\\ x'=x'' \\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-0\pm \sqrt{324} }{2*1} \to x= \frac{-0\pm 18 }{2} \to \\\\\\ x= \frac{-0+18 }{2} \to x= \frac{18 }{2} \to x'=9\\\\\\ x''= \frac{-0- 18 }{2} \to x= \frac{-18 }{2} \to x''=-9\\\\\\\\ S=(-9;9)](https://tex.z-dn.net/?f=+x%5E%7B2%7D+-81%3D0%5C%5C%5C%5C+a%3D1%3Bb%3D0%3Bc%3D-81%5C%5C%5C%5C%5C%5C+%5CDelta%3Db%5E2-4ac%5Cto+%5CDelta%3D0%5E2-4%2A1%2A%28-81%29%5Cto+%5CDelta%3D0%2B324%5Cto+%5CDelta%3D324%5C%5C%5C%5C+x%27%3Dx%27%27+%5C%5C%5C%5C%5C%5C+x%3D+%5Cfrac%7B-b%5Cpm+%5Csqrt%7B%5CDelta%7D+%7D%7B2a%7D+%5Cto+x%3D+%5Cfrac%7B-0%5Cpm+%5Csqrt%7B324%7D+%7D%7B2%2A1%7D+%5Cto+x%3D+%5Cfrac%7B-0%5Cpm+18+%7D%7B2%7D+%5Cto+%5C%5C%5C%5C%5C%5C+x%3D+%5Cfrac%7B-0%2B18+%7D%7B2%7D+%5Cto+x%3D+%5Cfrac%7B18+%7D%7B2%7D+%5Cto+x%27%3D9%5C%5C%5C%5C%5C%5C+x%27%27%3D+%5Cfrac%7B-0-+18+%7D%7B2%7D+%5Cto+x%3D+%5Cfrac%7B-18+%7D%7B2%7D+%5Cto+x%27%27%3D-9%5C%5C%5C%5C%5C%5C%5C%5C+S%3D%28-9%3B9%29)
Perceba que o resultado não muda, assim você pode escolher a forma de resolver que considerar mais fácil...
Mas vou colocar a fórmula de Bhaskara aqui tbm:
Perceba que o resultado não muda, assim você pode escolher a forma de resolver que considerar mais fácil...
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