Question

Ajudem pfv na questao "d"

Answer 1

$(\sqrt{10})^x\cdot(0,01)^{4x-1}= \frac{1}{1000} \\ \\(10^{\frac{1}{2}})^x \cdot(10^{-2})^{4x-1}= 10^{-3}\\ \\10^{\frac{x}{2}-8x+2}= 10^{-3}\\ \\\frac{x}{2}-8x+2= -3\\ \\\frac{x-16x+4}{2}= -3\\ \\x-16x+4=2\cdot(-3)\\ \\x-16x+4=-6\\ \\x-16x=-6-4\\ \\-15x=-10\\ \\x= \frac{-10^{:5}}{-15_{:5}} \\ \\x= \frac{2}{3} \\ \\S=\{ \frac{2}{3} \}$