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6. Seja o valor de um M e igual a
( Conta na foto )
7. O valor da expressão
( Conta na foto )
8. Qual o valor de Y ?
( Conta na foto )
10. O valor da expressão é
( Conta na foto )
Anexos:
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Soluções para a tarefa
Respondido por
1
6)

Alternativa C
7)
![10^-^2[(-3)^2-(-2)^3]: \sqrt[3]{-0,001} = \\ \frac{1}{10^2}[9-(-8)]: \sqrt[3]{-0,001} = \\ \frac{1}{100} [9+8]: \sqrt[3]{-0,001} = \\ \frac{1}{100}.17 \sqrt[3]{-0,001} = \\ \frac{17}{100}: \sqrt[3]{- \frac{1}{1000} }= \\ \frac{17}{100}: (- \frac{1}{10}) =\\ \frac{17}{100} . (- \frac{10}{1}) = \\ - \frac{170}{100} = \\ -1,7 10^-^2[(-3)^2-(-2)^3]: \sqrt[3]{-0,001} = \\ \frac{1}{10^2}[9-(-8)]: \sqrt[3]{-0,001} = \\ \frac{1}{100} [9+8]: \sqrt[3]{-0,001} = \\ \frac{1}{100}.17 \sqrt[3]{-0,001} = \\ \frac{17}{100}: \sqrt[3]{- \frac{1}{1000} }= \\ \frac{17}{100}: (- \frac{1}{10}) =\\ \frac{17}{100} . (- \frac{10}{1}) = \\ - \frac{170}{100} = \\ -1,7](https://tex.z-dn.net/?f=10%5E-%5E2%5B%28-3%29%5E2-%28-2%29%5E3%5D%3A+%5Csqrt%5B3%5D%7B-0%2C001%7D+%3D+%5C%5C+%5Cfrac%7B1%7D%7B10%5E2%7D%5B9-%28-8%29%5D%3A+%5Csqrt%5B3%5D%7B-0%2C001%7D+%3D+%5C%5C+%5Cfrac%7B1%7D%7B100%7D+%5B9%2B8%5D%3A+%5Csqrt%5B3%5D%7B-0%2C001%7D+%3D+%5C%5C+%5Cfrac%7B1%7D%7B100%7D.17+%5Csqrt%5B3%5D%7B-0%2C001%7D+%3D+%5C%5C+%5Cfrac%7B17%7D%7B100%7D%3A+%5Csqrt%5B3%5D%7B-+%5Cfrac%7B1%7D%7B1000%7D+%7D%3D+%5C%5C+%5Cfrac%7B17%7D%7B100%7D%3A+%28-+%5Cfrac%7B1%7D%7B10%7D%29+%3D%5C%5C+%5Cfrac%7B17%7D%7B100%7D+.+%28-+%5Cfrac%7B10%7D%7B1%7D%29+%3D+%5C%5C+-+%5Cfrac%7B170%7D%7B100%7D+%3D+%5C%5C+-1%2C7)
Alternativa B
8)

Alternativa C
9)

Alternativa D
10)

Alternativa C
Alternativa C
7)
Alternativa B
8)
Alternativa C
9)
Alternativa D
10)
Alternativa C
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