Question

AJUDEM AMIGOS PRECISO MUITO

Answer 1

$a)\ x^2-49=0\\\\ x^2=49\\\\ x=\pm\sqrt{49}\\\\ x=\pm7\\\\ x=+7\ \ \ e\ \ \ x=-7\\\\\\ b)\ 2x^2=50\\\\ x^2=\frac{50}{2}\\\\ x^2=25\\\\ x=\pm\sqrt{25}\\\\ x=\pm5\\\\ x=+5\ \ \ e\ \ \ x=-5$


$c)\ x^2-1=0\\\\ x^2=1\\\\ x=\pm\sqrt{1}\\\\ x=\pm1\\\\ x=+1\ \ \ e\ \ \ x=-1\\\\\\ d)\ 8x^2-8=0\\\\ 8x^2=8\\\\ x^2=\frac{8}{8}\\\\ x^2=1\\\\ x=\pm\sqrt{1}\\\\ x=\pm1\\\\ x=+1\ \ \ e\ \ \ x=-1$


$e)\ 4x^2-20=0\\\\ 4x^2=20\\\\ x^2=\frac{20}{4}\\\\ x^2=5\\\\ x=\pm\sqrt{5}\\\\ x=+\sqrt{5}\ \ \ e\ \ \ x=-\sqrt{5}$


$f)\ -25+x^2=0\\\\ x^2=25\\\\ x=\pm\sqrt{25}\\\\ x=\pm5\\\\ x=+5\ \ \ e\ \ \ x=-5\\\\\\ g)\ 7x^2+2=30\\\\ 7x^2=30-2\\\\ 7x^2=28\\\\ x^2=\frac{28}{7}\\\\ x^2=4\\\\ x=\pm\sqrt{4}\\\\ x=\pm2\\\\ x=+2\ \ \ e\ \ \ x=-2$


$h)\ x^2+16=0\\\\ x^2=-16\\\\ x=\pm\sqrt{-16}\\\\ x=\pm4\sqrt{-1}\ (n\~ao\ tem\ solu\c{c}\~ao\ no\ campo\ dos\ n\'umeros\ reais)\\\\ x=+4\sqrt{-1}\ \ \ e\ \ \ x=-4\sqrt{-1}$


Bons estudos!