Question

ajudem :$ .agora acho que da pra ler

Answer 1

4-) $F= k. \frac{Q_{1}.Q_{2}}{d^{2} }$

d = 70 cm = 0,7 m
k= 9.10^9

$F= 9.10^{9} . \frac{10^{-6} .6.10^{-6}}{0,7 ^{2} } = \frac{54.10^{9}. 10^{-12} }{0,49}$

$F = \frac{54.10^{-3} }{0,49 }$

F = 0,1102 N

5-) $F= k. \frac{Q}{d^{2} }$

$F= k. \frac{Q}{d^{2} } > F. d^{2} = k.Q$

$Q = \frac{F.d^{2} }{k} = \frac{3,6.1^{2} }{9.10^{9} } = 0,4.10^{-9}$

$Q = 4.10^{-8} C$