Matemática, perguntado por silvathamyres2pelnmx, 11 meses atrás

Ajudem a questão 4,5,10 e 12

Anexos:

Soluções para a tarefa

Respondido por gsp477
0

4)

a)

 \sqrt[3]{343}  =  \sqrt[3]{ {7}^{3} } = 7

b)

 \sqrt[3]{64}  =  \sqrt[3]{ {2}^{6} } =  {2}^{ \frac{6}{3} }   =  {2}^{2}  = 4

c)

 \sqrt[3]{125}  =  \sqrt[3]{ {5}^{3} }  = 5

d)

 \sqrt[3]{512}  =  \sqrt[3]{ {2}^{9} }  =  {2}^{ \frac{9}{3} }  =  {2}^{3}  = 8

e)

 \sqrt[3]{729}  =  \sqrt[3]{ {3}^{6} }  =  {3}^{ \frac{6}{3} }  = 3 {}^{2}  = 9

f)

 \sqrt[3]{1000}  =  \sqrt[3]{ {10}^{3} }  = 10

g)

 \sqrt[3]{216}  =  \sqrt[3]{ {3}^{3} \times  {2}^{3}  }  = 3 \times 2 = 6

5)

a)

t + 14 =  \frac{t}{2}  - 18 \\  \\ 2(t + 14) = 2( \frac{t}{2}  - 18) \\  \\ 2t + 28 = t - 36 \\  \\ 2t - t =  - 36 - 28 \\  \\ t =   -  64

b)

2h  - 15 = 20 \\  \\ 2h = 20 + 15 \\  \\ 2h = 35 \\  \\ h =  \frac{35}{2}   \\ \\ h = 17.5

c)

30 - 5g = g + 25 \\  \\  - 5g - g = 25 - 30 \\  \\  - 6g =  - 5 \\  \\ g =  \frac{ - 5}{ - 6}  \\  \\ g =  \frac{5}{6}

d)

3y - 20 = 27 - 18 \\  \\ 3y = 27 - 18 + 20 \\  \\ 3y = 29 \\  \\ y =  \frac{29}{3}  \\  \\

10)

Escala 1cm representa 40000cm reais.

 \frac{1cm}{40000cm}  =  \frac{38 \times 10 {}^{ - 1}cm  }{r}  \\  \\  \\ 1cmr = (4 \times 10 {}^{4} cm) \times (38 \times 10 {}^{ - 1} cm) \\  \\ 1cmr = 152 \times 10 {}^{3} cm {}^{2}  \\  \\ 1cmr = 152000cm {}^{2}  \\  \\  \frac{1cmr}{1cm}  =  \frac{152000cm {}^{2} }{1cm}  \\  \\ r = 152000cm

r=1520000mm=152000cm=15200dm=1520m=152dam=15,2hm=1,52km

12)

 \frac{35}{100}  \times  \frac{840}{1}  =  \frac{29400}{100}  =  294

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