Question

ajude-me nesta questão de limite trigonometrico

Answer 1

$\boxed{\sin{2x}=2\sin{x}\cos{x}}$

$\lim\limits_{x \to 0} \dfrac{\sin{2x}}{\sin{x}}= \lim\limits_{x \to 0} \dfrac{2\sin{x}\cos{x}}{\sin{x}}=$

$\lim\limits_{x \to 0} 2\cos{x}=2\cos{0}=\boxed{2}$