Ajude eu nas operação
A)0,1313...+0,1414...
B)2,333...
1,555...
C)6,111...-3,111...
D) 7,222...×1,777...
Soluções para a tarefa
Respondido por
1
100x = 13,13
x= 0,1313 Corta a parte decimal
99x = 13
x = 13/99
100x= 14,14
x= 0,14
99x= 14
x= 14/99
Ai fica 13/99+14/99
= 27/99
x= 0,1313 Corta a parte decimal
99x = 13
x = 13/99
100x= 14,14
x= 0,14
99x= 14
x= 14/99
Ai fica 13/99+14/99
= 27/99
Respondido por
1
0,1313...
+ 0,1414...
0,2727...
B)![\frac{2,33...}{1,55...} = \frac{2,33...}{1,55...} =](https://tex.z-dn.net/?f=+%5Cfrac%7B2%2C33...%7D%7B1%2C55...%7D+%3D)
![2,333... = \frac{23-2}{9}= \frac{21}{9} 2,333... = \frac{23-2}{9}= \frac{21}{9}](https://tex.z-dn.net/?f=2%2C333...+%3D++%5Cfrac%7B23-2%7D%7B9%7D%3D+%5Cfrac%7B21%7D%7B9%7D++)
![1,555...= \frac{15-1}{9}= \frac{14}{9} 1,555...= \frac{15-1}{9}= \frac{14}{9}](https://tex.z-dn.net/?f=1%2C555...%3D+%5Cfrac%7B15-1%7D%7B9%7D%3D+%5Cfrac%7B14%7D%7B9%7D++)
![\frac{21}{9}: \frac{14}{9}= \frac{21}{9}. \frac{9}{14}= \frac{21}{14} = \frac{3}{2}=1,5 \frac{21}{9}: \frac{14}{9}= \frac{21}{9}. \frac{9}{14}= \frac{21}{14} = \frac{3}{2}=1,5](https://tex.z-dn.net/?f=+%5Cfrac%7B21%7D%7B9%7D%3A+%5Cfrac%7B14%7D%7B9%7D%3D++%5Cfrac%7B21%7D%7B9%7D.+%5Cfrac%7B9%7D%7B14%7D%3D+%5Cfrac%7B21%7D%7B14%7D+%3D+%5Cfrac%7B3%7D%7B2%7D%3D1%2C5++++)
C) 6,111...
- 3,111...
3,111...
D) 7,222... x 1,777... =
![7,222...= \frac{72-7}{9}= \frac{65}{9} 7,222...= \frac{72-7}{9}= \frac{65}{9}](https://tex.z-dn.net/?f=7%2C222...%3D++%5Cfrac%7B72-7%7D%7B9%7D%3D+%5Cfrac%7B65%7D%7B9%7D++)
![1,777...= \frac{17-1}{9} = \frac{16}{9} 1,777...= \frac{17-1}{9} = \frac{16}{9}](https://tex.z-dn.net/?f=1%2C777...%3D+%5Cfrac%7B17-1%7D%7B9%7D+%3D+%5Cfrac%7B16%7D%7B9%7D+)
![\frac{65}{9} . \frac{16}{9}= \frac{1040}{81}=12,83 aproximadamente \frac{65}{9} . \frac{16}{9}= \frac{1040}{81}=12,83 aproximadamente](https://tex.z-dn.net/?f=+%5Cfrac%7B65%7D%7B9%7D+.++%5Cfrac%7B16%7D%7B9%7D%3D+%5Cfrac%7B1040%7D%7B81%7D%3D12%2C83+aproximadamente+++)
+ 0,1414...
0,2727...
B)
C) 6,111...
- 3,111...
3,111...
D) 7,222... x 1,777... =
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