Question

Ajudam -me só simplificar esses exercícios,da linha 3 e 2

Answer 1

sen² β + cos² β = 1
cos² β = 1 - sen² β
cos² β = 1 - (1/3)²
cos² β = √8/√3 = √24/3

$\frac{sen^2\: x}{sen\: xcos^2\: x + sen^3\: x} = \frac{sen^2\: x}{sen\: x(cos^2\: x + sen^2\: x)} = \frac{sen\: x}{cos^2\: x + sen^2\: x} = sen\: x$

$\frac{cos\: x - cos\: xsen^2\: x}{cos^3\: x + sen^2\: xcos\: x} = \frac{sen^2\: xcos\: x(sen^2\: x - 1)}{sen^2\: xcos\: x(sen^2\: xcos^2\: x + 1)} = \frac{sen^2\: x - 1}{sen^2\: xcos^2\: x + 1}$