Matemática, perguntado por iv142416, 5 meses atrás

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Anexos:

Soluções para a tarefa

Respondido por ToquioItuno
2

\Large\boxed{\boxed{\boxed{{Ola\´\ }}}}}

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a)

 \sf {( - 3)}^{ - 1}  +  {( - 1)}^{ - 3}  \\  \\  \sf {- 3}^{ - 1}   -   {1}^{ - 3} \\ \\    \sf-  \frac{1}{3}  -  {1}^{ - 3}  \\ \\   \sf-  \frac{1}{3}  -  1 \\ \\   \sf -  \frac{1 + 3}{3}  \\ \\  \large\boxed{{\sf  \blue-  \frac{ \blue4}{ \blue3} {}}}  \\

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b)

 \sf  { 2}^{ - 4}  -  {2}^{2}  \\  \\  \sf \frac{1}{ {2}^{4} }  -  {2}^{2}  \\  \\ \sf \frac{1}{ {2}^{4} }  -  4 \\  \\\sf \frac{1}{ 16}  -  4  \\  \\\sf \frac{1  -  64}{16}  \\ \\  \large\boxed{{\sf \blue - \frac{  \blue6 \blue3}{ \blue1 \blue6} {}}}  \\

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c)

 \sf {( {4}^{ - 2} + {2}^{ - 3}   )}^{ - 1} \\  \\ \sf {( {2}^{ - 4} + {2}^{ - 3}   )}^{ - 1} \\  \\ \sf {( {2}^{ - 4} +  \frac{1}{ {2}^{3} }  )}^{ - 1} \\  \\  \sf {(  \frac{1}{ {2}^{4} } +  \frac{1}{ {2}^{3} }  )}^{ - 1} \\  \\ \sf {(  \frac{1}{ 16 } +  \frac{1}{ 8}  )}^{ - 1} \\  \\ \sf {(  \frac{3}{ 16 }  )}^{ - 1} \\  \\ \large\boxed{{\sf  \frac{  \blue1 \blue6}{ \blue3} {}}}  \\

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d)

 \sf {( {6}^{ - 2}  \times  {3}^{2}   )}^{ - 1} \\  \\ \sf {(  \frac{1}{ {6}^{2} }  \times  {3}^{2}  )}^{ - 1} \\  \\ \sf {(  \frac{1}{ {2}^{2} \times  {3}^{2}  }  \times  {3}^{2}  )}^{ - 1} \\  \\ \sf {(  \frac{1}{ {2}^{2} }  )}^{ - 1} \\  \\  \sf {(  \frac{1}{ 4 }  )}^{ - 1} \\  \\\large\boxed{{\sf  \blue4 {}}}  \\

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