Question

AJUDAAAAAAAAAAAAAAAAAAA

Answer 1

$\left[\begin{array}{ccc}1&m&1\\m&1&-1\\1&0&-1\end{array}\right]=m^{2}-m-2=0\\ \\\left \{ {{x1=2} \atop {x2=-1}} \right.$

$m\neq 2$

e

$m\neq -1$