Question

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Answer 1

a) V = Δ distancia / Δ tempo

V = 11 - 2 / 4 - 1

V = 9 / 3 = 3m/s

b) Sf = So + V*T          

2 = So + 3*1

So = 2 - 3 = -1

Sf = -1 + 3*T  ( Equação horaria )

c) Sf = -1 + 3*2

Sf = -1 + 6 = 5

d) 17 = -1 + 3*T

17 + 1 = 3T

T = 18 / 3 = 6