Question

ajudaaaaaaaaaaaaaaaaaa​

Answer 1

Bom Dia

Log(9, 27) = x

Log₉ 27 = x

9 ^ x = 27

$\sqrt{9} = 3$

3² = 27

Então $(\sqrt{9})^{3} = 27$

Podemos determinar $\sqrt{9} = 9^{\frac{1}{2}}$

$(9^{\frac{1}{2}})^{3} = 9^{\frac{3}{2}}$

$9^{x} = 9^{\frac{2}{3}}$

X = $\frac{2}{3}$

Espero ter ajudado!