Question

Ajudaaaaaaaaa plisssssssss ☺❤❤❤

Answer 1

$\frac{(3x-2)^2}{6}=\frac{(2x+3)}{3}-\frac{x(1-5x)}{2}\\\\\\\frac{9x^2-12x+4}{6}=\frac{2x+3}{3}-\frac{x-5x^2}{2}\\\\\\9x^2-12x+4=2(2x+3)-3(x-5x^2)\\\\\\9x^2-12x+4-x-6-15x^2=0\\\\\\-6x^2-13x-2=0\\\\\\x1=-2\\\\x2=-\frac{1}{6}$