Question

Ajudaaaaa!!!!
(Xm-Yn)²


(3a³-5b²)²

Answer 1

$(a-b)^2=a^2-2ab+b^2$

Portanto:

$(xm-yn)^2=\\(xm)^2-2xmyn+(yn)^2=\\x^2m^2-2mnxy+y^2n^2$ 

$(3a^3-5b^2)^2=\\(3a^3)^2-2.3a^3.5b^2+(5b^2)^2=\\3^2a^6-30a^3b^2+5^2b^4=\\9a^6-30a^3b^2+25b^4$