Question

Ajudaaaaa porfavorzinhoo

Answer 1

Resposta:

Explicação passo-a-passo:

21-a) $\frac{(a^3b^2)^5 }{(a^4b^4)^3}$ = $a^{15}$$b^{10}$/ $a^{12} b^{12}$

$a^{15-12}$$b^{10-12}$

$a^{3} b^{-2}$

$\frac{a^3}{b^2}$

b) $\frac{(a^-^2b)^-^5}{(a^-^3b^2)^-^4}$ = $a^{10} b^{-5}$ / $a^{12} b^{-8}$

$a^{10-12} b^{-5-(-8)}$

$a^{-2} b^{3}$

$\frac{b^3}{a^2}$

23-a) $\frac{3^9.9^-^2}{27^7.81^-^5}$ = $\frac{3^{9} . (3^2)^-^2}{(3^3)^7 .(3^4)^-^5}$

         $\frac{3^9.3^-^4}{3^2^1 . 3^-^2^0}$ = $\frac{3^9^+^(^-^4^)}{3^2^1^+^(^-^2^0^)}$

           $\frac{3^5}{3} = 3^5^-^1 = 3^4$

b) $\frac{3^6.27^6}{243^3}$ = $\frac{3^6.(3^3)^6}{(3^5)^3}$

   $\frac{3^6.3^1^8}{3^1^5}$ = $\frac{3^2^4}{3^1^5}$

   $3^{24 - 15}$ = $3^{9}$