Question

⚠️AJUDAAAAA piiiis...⚠️

Answer 1

$m_A=3,0kg\\v_A=2,0m/s\\m_B=1,0kg\\v_B = 0\\\\Q_{inicial} = Q_{final}\\Q_A + Q_B = Q_{final}\\m_Av_A + m_Bv_B= (m_A+m_B)v\\3 \cdot 2 + 1 \cdot 0 = (3 + 1)v\\4v = 6 \\4v = 6\\v = \dfrac 64\\\boxed{v = 1,5m/s}$