Question

AJUDAAA PFVV!!! Pra amanhAa

Answer 1

$IDH-R= \frac{logP\ \/- \ \/2}{2,6} \\ \\ \frac{10}{13} = \frac{logP\ \/- \ \/2}{2,6}\\ \\ logP\ \/- \ \/2= \frac{2,6\cdot10}{13} \\\\ logP\ \/- \ \/2= 2\\ \\log\ \/P=2+2 \\\\logP=4\\\\ P=10^4 \\\\P=10000$