Question

ajudaa urgenteeee!!!!!!!!!!!!!!!!!
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Answer 1

Resposta:

D-)

$2(x + 4) + 3(x + 2) = 2x + 12$

$2x + 8 + 3x + 6 = 2x + 12$

$8 + 3x + 6 = 12$

$14 + 3x = 12$

$3x = 12 - 14$

$3x = - 2$

$x = - \frac{2}{3}$

E-)

$(x - 5) \times 10 + (1 - 2x) \times 5 = (3 - x) \times 4$

$(x - 5) \times 10x + 5 - 10x = 12 - 4x$

$10 {x}^{2} - 50x + 5 - 10x = 12 - 4x$

$10 {x}^{2} - 60x + 5 = 12 - 4x$

$10 {x}^{2} - 60x + 5 - 12 + 4x = 0$

$10 {x}^{2} - 56x - 7 = 0$

$x = \frac{ - ( - 56) + - \sqrt{ {( - 56)}^{2} - 4 \times 10 \times ( - 7) } }{2 \times 10}$

$x = \frac{56 + - \sqrt{3136 + 280} }{20}$

$x = \frac{56 + - \sqrt{3416} }{20}$

$x = \frac{56 + - 2 \sqrt{854} }{20}$

$x = \frac{56 + 2 \sqrt{854} }{20}$

$x = \frac{56 - 2 \sqrt{854} }{20}$

$x = \frac{28 + \sqrt{854} }{10}$

$x = \frac{28 - \sqrt{854} }{10}$

$x1 = \frac{28 - \sqrt{854} }{10}$

$x2 = \frac{28 + \sqrt{854} }{10}$

Answer 2

Resposta:

a opção D)

espero ter ajudado