Question

ajuda urgenteeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answer 1

Resposta:

a) f(1)= 3• 1^2- 4.1+ 1=

f(1)= 3- 3= 0

b) f(2)= 3• 2^2- 4•2+ 1=

f(2)= 3•4 -7=

f(2)= 12-7=

f(2)= 5

c) f(0)= 3•0^2- 4•0+1=

f(0)= 1

d) f(2)= 3• (-2)^2- 4•(-2)+1=

f(2)= 3 +4 +8+ 1=

f(2)= 16