Question

Ajuda, questão de física ​

Answer 1

9

$Q=mc\Delta T \\ 16 \cdot {10}^{3} = 10 \cdot c \cdot \: 80 \\ 800c = 16 \cdot {10}^{3} \\ c = \frac{16 \cdot {10}^{3}}{8 \cdot {10}^{2}} = 2 \cdot10 = 20$

10

$\Delta U = Q - \tau \\ - 1,5 \ {10}^{4} = 3 \cdot {10}^{3} - \tau \\ \tau = 3\cdot {10}^{3} + 15\cdot {10}^{3} \\ \tau = 18\cdot {10}^{3} = 1,8\cdot {10}^{4}J$