Question

AJUDA :)
Qual a temperatura de equilibrio ao se mistura os dois liquidos a seguir: (Liquido 1: m = 400 g, c = 2 cal/g °C, To= 50 °CLiquido 2: m = 600 g, c = 1,8 cal/g °C, To= 99 °C)

A) 6,56 °C
B) 78,14 °C
C) 60,54 °C
D) 52,55 °C

Answer 1

Pela formula do equilibrio térmico

Q1 + Q2 = 0

Q1 = m × c × ( Tf - Ti )

Q2 = m × c × ( Tf - Ti )

m × c × ( Tf × Ti ) + m × c × ( Tf × Ti ) = 0

400 × 2 × ( Tf - 50 ) + 600 × 1,8 × ( Tf - 99 ) = 0

800 × ( Tf - 50 ) + 1080 × ( Tf - 99 ) = 0

800.Tf - 40000 + 1080.Tf - 106920 = 0

( 800.Tf + 1080.Tf ) ( - 40000 - 106920 ) = 0

1880.Tf - 146920 = 0

1880.Tf = 146920

Tf = $\frac{146920}{1880}$

Tf = 78,14°C

alternativa b)