Question

ajuda preciso até 12:00pm

b)
${m}^{2} - 2mn + {n}^{2} \\ m = 1 \: e \: n = \frac{1}{4}$

Answer 1

1)
$\frac{t}{m + 3} =\ \textgreater \ \frac{43,2}{1,5 +3}=\ \textgreater \ \frac{43,2}{4,5}=9,6$

2)
a) $\frac{ a^{2} -2}{ \sqrt{a} }=\ \textgreater \ \frac{16-2}{2} =7$

b) $m^{2}-2mn+ n^{2}=\ \textgreater \ 1 ^{2}-2*1*( \frac{1}{4} )+( \frac{1}{4} )^{2}$
$1- \frac{1}{2} + \frac{1}{16} =\ \textgreater \ \frac{16-8+1}{16} = \frac{9}{16}$